luogu4717(FWT/FMT模板)

题目链接

https://www.luogu.org/problemnew/show/P4717

题解

$FWT$ 和 $FMT$ 的推导过程参考这个链接

异或的卷积用 $FWT$ ,然后与和或的可以考虑用 $FMT$ 比 $FWT$ 好写得多




代码

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/**
*         ┏┓    ┏┓
*         ┏┛┗━━━━━━━┛┗━━━┓
*         ┃       ┃  
*         ┃   ━    ┃
*         ┃ >   < ┃
*         ┃       ┃
*         ┃... ⌒ ...  ┃
*         ┃ ┃
*         ┗━┓ ┏━┛
*          ┃ ┃ Code is far away from bug with the animal protecting          
*          ┃ ┃ 神兽保佑,代码无bug
*          ┃ ┃           
*          ┃ ┃       
*          ┃ ┃
*          ┃ ┃           
*          ┃ ┗━━━┓
*          ┃ ┣┓
*          ┃ ┏┛
*          ┗┓┓┏━━━━━━━━┳┓┏┛
*           ┃┫┫ ┃┫┫
*           ┗┻┛ ┗┻┛
*/

#include<cstdio>
#include<cstring>
#include<algorithm>
#include<iostream>
#include<queue>
#include<map>
#include<stack>
#include<cmath>
#include<set>
#include<bitset>
#include<complex>
#include<cstdlib>
#include<assert.h>
#define inc(i,l,r) for(int i=l;i<=r;i++)
#define dec(i,l,r) for(int i=l;i>=r;i--)
#define link(x) for(edge *j=h[x];j;j=j->next)
#define mem(a) memset(a,0,sizeof(a))
#define mid ((x+y)/2)
#define ll long long
#define eps 1e-8
#define succ(x) (1<<x)
#define lowbit(x) (x&(-x))
#define sqr(x) ((x)*(x))
#define NM 200005
#define nm 400005
using namespace std;
const double pi=acos(-1);
const ll inf=998244353;
ll read(){
ll x=0,f=1;char ch=getchar();
while(!isdigit(ch)){if(ch=='-')f=-1;ch=getchar();}
while(isdigit(ch))x=x*10+ch-'0',ch=getchar();
return f*x;
}


int n;
ll a[NM],b[NM],c[NM],d[NM];

struct FWT{
int n;
ll b[NM];
void fwt(ll*a,int f){
if(f==-1)f=inf+1>>1;
for(int k=1;k<n;k<<=1)
for(int i=0;i<n;i+=k<<1)
for(int j=0;j<k;j++){
ll x=a[i+j],y=a[i+j+k];
a[i+j]=f*(x+y)%inf;
a[i+j+k]=f*(x-y+inf)%inf;
}
}
int plu(ll*a,ll*_b,int p,int m){
inc(i,0,m-1)b[i]=_b[i];
for(n=1;n<p||n<m;n<<=1);
fwt(a,1);fwt(b,1);inc(i,0,n-1)a[i]=a[i]*b[i]%inf;
fwt(a,-1);inc(i,0,n-1)b[i]=0;return n;
}
}fwt;

struct FMTor{
int n;
ll b[NM];
void fmt(ll*a,int f){
for(int i=0;succ(i)<n;i++)
inc(j,0,n-1)if(j>>i&1)
a[j]=(a[j]+f*a[j^1<<i]+inf)%inf;
}
int plu(ll*a,ll*_b,int p,int m){
inc(i,0,m-1)b[i]=_b[i];
for(n=1;n<p||n<m;n<<=1);
fmt(a,1);fmt(b,1);inc(i,0,n-1)a[i]=a[i]*b[i]%inf;
fmt(a,-1);inc(i,0,n-1)b[i]=0;return n;
}
}fmtor;

struct FMTand{
int n;
ll b[NM];
void fmt(ll*a,int f){
for(int i=0;succ(i)<n;i++)
dec(j,n-1,0)if(~j>>i&1)
a[j]=(a[j]+f*a[j|1<<i]+inf)%inf;
}
int plu(ll*a,ll*_b,int p,int m){
inc(i,0,m-1)b[i]=_b[i];
for(n=1;n<p||n<m;n<<=1);
fmt(a,1);fmt(b,1);inc(i,0,n-1)a[i]=a[i]*b[i]%inf;
fmt(a,-1);inc(i,0,n-1)b[i]=0;return n;
}
}fmtand;


int main(){
n=1<<read();
inc(i,0,n-1)a[i]=c[i]=d[i]=read();
inc(i,0,n-1)b[i]=read();
fmtand.plu(a,b,n,n);
fmtor.plu(c,b,n,n);
fwt.plu(d,b,n,n);
inc(i,0,n-1)printf("%lld%c",c[i]," \n"[i==n-1]);
inc(i,0,n-1)printf("%lld%c",a[i]," \n"[i==n-1]);
inc(i,0,n-1)printf("%lld%c",d[i]," \n"[i==n-1]);
return 0;
}