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| #include<cstdio> #include<cstring> #include<algorithm> #include<iostream> #include<queue> #include<map> #include<stack> #include<cmath> #include<set> #include<bitset> #include<assert.h> #define inc(i,l,r) for(int i=l;i<=r;i++) #define dec(i,l,r) for(int i=l;i>=r;i--) #define link(x) for(edge *j=h[x];j;j=j->next) #define mem(a) memset(a,0,sizeof(a)) #define ll long long #define eps 1e-6 #define succ(x) (1<<x) #define lowbit(x) (x&(-x)) #define sqr(x) ((x)*(x)) #define mid (x+y)/2 #define NM 105 #define nm 170005 #define pi 3.1415926535897931 const ll inf=1e9+7; using namespace std; ll read(){ ll x=0,f=1;char ch=getchar(); while(!isdigit(ch)){if(ch=='-')f=-1;ch=getchar();} while(isdigit(ch))x=x*10+ch-'0',ch=getchar(); return f*x; }
ll n,m; struct mat{int n,m;ll a[NM][NM];}null,ans,t; mat operator*(const mat&x,const mat&y){ mat s;s.n=x.n;s.m=y.m;mem(s.a); inc(i,1,s.n)inc(j,1,s.m)inc(k,1,x.m)(s.a[i][j]+=x.a[i][k]*y.a[k][j]%inf)%=inf; return s; } mat qpow(mat x,ll t){return t?qpow(sqr(x),t>>1)*(t&1?x:null):null;}
int main(){ n=read();m=read(); ans.n=m;ans.m=1; inc(i,1,m)ans.a[i][1]=1; t.n=t.m=m; inc(i,1,m-1)t.a[i][i+1]=1; t.a[m][1]=t.a[m][m]=1; null.n=null.m=m; inc(i,1,m)null.a[i][i]=1; if(n>=m)ans=qpow(t,n-m+1)*ans; printf("%lld\n",ans.a[m][1]); return 0; }
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